To get the string after a specific character in Oracle, you can use the SUBSTR function along with the INSTR function. First, use the INSTR function to find the position of the character in the string. Then, use the SUBSTR function to extract the substring after that position. For example, if you want to get the string after the character '@' in the email address 'example@example.com', you can use the following query: SELECT SUBSTR('example@example.com',INSTR('example@example.com','@')+1) FROM dual; This will return 'example.com' as the output.
How to extract part of a string after a character in Oracle?
To extract part of a string after a character in Oracle, you can use the SUBSTR
and INSTR
functions together. Here is an example of how you can extract part of a string after a specific character, such as a comma:
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SELECT SUBSTR(column_name, INSTR(column_name, ',') + 1) FROM table_name; |
In this query, column_name
is the name of the column from which you want to extract the substring, and table_name
is the name of the table containing the column. The INSTR
function is used to find the position of the comma in the string, and the SUBSTR
function is used to extract everything after the comma.
You can modify the query to use a different character by replacing the comma in the INSTR
function with the character of your choice.
How to retrieve characters after a delimiter in Oracle?
To retrieve characters after a delimiter in Oracle, you can use the SUBSTR
function in combination with the INSTR
function. Here's an example:
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SELECT SUBSTR(column_name, INSTR(column_name, 'delimiter') + 1) AS characters_after_delimiter FROM your_table_name; |
In this example, replace column_name
with the name of the column containing the text you want to extract characters from, delimiter
with the actual delimiter you want to use, and your_table_name
with the name of your table.
The INSTR
function is used to find the position of the delimiter within the text, and then the SUBSTR
function is used to extract characters starting from the position after the delimiter.
This query will return the characters after the specified delimiter for each row in your table.
How to split a string and extract the remainder in Oracle?
To split a string and extract the remainder in Oracle, you can use the SUBSTR
function along with the INSTR
function to find the position of the delimiter in the string. Here is an example:
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-- Input string DECLARE v_input_string VARCHAR2(100) := 'Hello World,How Are You?'; v_delimiter VARCHAR2(1) := ','; v_remainder VARCHAR2(100); v_split_index NUMBER; BEGIN -- Find the position of the delimiter v_split_index := INSTR(v_input_string, v_delimiter); IF v_split_index > 0 THEN -- Extract the remainder of the string after the delimiter v_remainder := SUBSTR(v_input_string, v_split_index + 1); DBMS_OUTPUT.PUT_LINE('The remainder of the string is: ' || v_remainder); ELSE DBMS_OUTPUT.PUT_LINE('Delimiter not found in the string'); END IF; END; |
In this example, we are splitting the input string "Hello World,How Are You?" at the comma (,) delimiter, and extracting the remainder of the string after the delimiter. The INSTR
function is used to find the position of the delimiter, and the SUBSTR
function is then used to extract the remainder of the string.
What is the technique to separate string after a particular character in Oracle?
The SUBSTR
and INSTR
functions in Oracle can be used to separate a string after a particular character.
Here's an example:
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SELECT SUBSTR('Hello, World', INSTR('Hello, World', ',') + 2) AS separated_string FROM dual; |
In this example, INSTR
is used to locate the position of the comma in the string 'Hello, World', and then SUBSTR
is used to extract the substring starting from the character after the comma.
This would return 'World' as the separated string.
How to find substring after a specific character in Oracle?
To find a substring after a specific character in Oracle, you can use the SUBSTR function along with the INSTR function. Here's an example of how you can do this:
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SELECT SUBSTR(your_column, INSTR(your_column, 'specific_character')+1) FROM your_table; |
In the above code snippet, replace 'your_column' with the name of the column from which you want to extract the substring and 'your_table' with the name of your table. Replace 'specific_character' with the character after which you want to find the substring.
This code will extract the substring after the specific character in the column specified.